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RSMSSB Common Eligibility Test (CET) Online Form 2022 Recruitment

RSMSSB is recruiting for Common Eligibility Test (CET) Online Form 2022 Posts. You can check RSMSSB - RSMSSB - Rajasthan Staff Selection Board last date, notification, official website and other details on SharmaJobs.Com. Complete Details about Common Eligibility Test (CET) Online Form 2022 vacancies in RSMSSB are given on SharmaJobs.com .

Quick Info

Form Type : Online Govt Jobs

Last Date : 11/11/2022

Company : RSMSSB - Rajasthan Staff Selection Board

Location : Rajasthan

Qualification : 12th Pass, Diploma

Advt. No : 10/2022

CBT. Date : 18, 19, 25, 26 February 2023

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Relaxations

Age Relaxation: Age Relaxation as per Govt Rule.

Selection Procedure

  1. Computer Based Test

The selection procedure for the post of Common Eligibility Test (CET) Online Form 2022 in RSMSSB will include the following stages: Computer Based Test, and other required tests.

Application Fee

CategoriesAmount
General / OBC450/-
OBC NCL350/-
SC / ST250/-
Correction Charge300/-
Mode of Payment Candidate have to pay Examination fees Through Emitra CSC Center, Debit Card, Credit Card, Net Banking.

Age Limit

as on 01/01/2023
Minimum Age 18 Year.
Maximum Age for Constable24 Year.
Maximum Age for Other Post40 Years.
age relaxation as per govt rule.

Vacancy Details

Department NamePost Name
Rajasthan Police Subordinate ServiceConstable
Rajasthan Forest Subordinate Service
Forester
Rajasthan Excise Subordinate service (Preventive Branch)
Jamadar Grade II
Rajasthan Minority Affairs Subordinate Service
Hostel Superintendent
Rajasthan Secretariat Clerical Service
Clerk Grade II
Rajasthan Subordinate Office Clerical ServiceJunior Assistant
Rajasthan Public Service Commission Office Clerical Service
Clerk Grade II

Vacancy Details

Common Eligibility Test

  • Qualification: Candidate Must Have Passed 10+2 Senior Secondary Exam in Any Recognized Board in India, Must Have Passed NIELIT O Level Exam / COPA / DPCS / NIOS Computer Operation Certificate / 3 Years Diploma in Computer Science Engineering / RSCIT. Please read official notification for post wise eligibility details.

The minimum qualification required for the post of Common Eligibility Test is: Candidate Must Have Passed 10+2 Senior Secondary Exam in Any Recognized Board in India, Must Have Passed NIELIT O Level Exam / COPA / DPCS / NIOS Computer Operation Certificate / 3 Years Diploma in Computer Science Engineering / RSCIT. Please read official notification for post wise eligibility details..

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How to Apply

  1. Candidate Can Apply through Online Mode.
  2. Click On the Apply Online Link given in Important Link Section.
  3. Read Instructions then Proceed to the online application.
  4. Fill All the Mandatory Details viz. Name, Father’s Name, Date of Birth, e-mail Address, Mobile Number, and Qualification, etc in the Application form.
  5. Follow the instructions and complete the registration process step-by-step for getting a Registration Number & Password.
  6. Upload the Scanned Copy of Documents in the Prescribed Size.
  7. Before submitting, the Application Form Must Check the Preview and All Column Carefully.
  8. Take Printout of your Application form for Future Reference.
  9. Online Application Can be Submitted on or Before 11th Nov 2022.

How to Apply

For the post of Common Eligibility Test (CET) Online Form 2022, the application process is online. Candidates can apply from the official online application link before 11/11/2022. The official notification PDF is also available.

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FAQs – Frequently Asked Questions

  • Q1: What is the last date to apply for Common Eligibility Test (CET) Online Form 2022?
  • A: The last date to apply is 11/11/2022.
  • Q2: What is the application process?
  • A: The application process is online.
  • Q3: How many vacancies are available?
  • A: There are multiple vacancies available.
  • Q4: What is the required qualification?
  • - 12th Pass
  • - Diploma
  • Q5: Where can I apply?
  • A: You can apply at the official website: Click Here.
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