Council Of Scientific and Industrial Research CSIR Online Are Invited Online Application Form for the NET / JRF Examination 2018. Those Candidates Are Interested in the Following Vacancy and Completed the All Eligibility Criteria Can Read the Full Notification and Apply Online.
Important Dates
Application Begin |
25/02/2019. |
Last Date for Complete Form |
22/03/2019. |
Date of Admit Card. |
June 2019 |
Date of Examination |
16/09/2019. |
Date of Result. |
Notified Soon |
Application Fees
General |
Rs.1000/-. |
OBC |
Rs.500/-. |
SC / ST / PH |
Rs.250/-. |
Mode of Payment |
Application Fee Can be Submitted through E-Challan Making Payment at Any Branch of Indian Bank. |
CSIR UGC NET / JRF June 2019 Examination Online Form Subject
1. Chemical Science. |
2. Earth, Atmospheric, Ocean and Planetary Sciences. |
3. Life Sciences. |
4. Mathematical Sciences. |
5. Physical Sciences. |
CSIR awards Junior Research Fellowship (JRF) to a large number of candidates each year. Educational background of candidates includes BS-4 years program, BE, B.Tech, B.Pharma, MBBS, Integrated BS-MS, MSc or equivalent, B.Sc Hons. |
Educational Qualification for CSIR UGC NET / JRF June 2019 Examination Online Form
UGC NET / JRF June 2019 Examination
Educational Qualifications |
Candidate Must Have Passed M.Sc or Equivalent Degree / BE / B.Tech / B.Pharma / MBBS with at least 55% Marks (50% for SC / ST and PH Candidates) or Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible for CSIR NET 2018. |
For More Details Please Check the Detailed Brochure. |
Age Limit Details of CSIR UGC NET / JRF June 2019 Examination Online Form
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As on 01/01/2019
Maximum Age for JRF |
28 Years. |
Maximum Age for NET |
No Age Limit. |
Age Relaxation As Per Govt Rules. |
Selection Process of CSIR UGC NET / JRF June 2019 Examination Online Form
Selection May be Based on.
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CSIR UGC NET / JRF June 2019 Examination Online Form Syllabus
Joint CSIR-UGC NET examination syllabus is formed keeping in mind the purpose of this exam. Syllabus of CSIR NET is divided into three parts namely Part A, Part B, Part C.
- Part A – This is common to all subjects. Questions will be on General Aptitude with emphasis on logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparison, series formation, puzzles.
- Part B – These will be subject-related conventional multiple choice questions.
- Part C – Here there will be higher value questions to test knowledge of scientific concepts and/or application of scientific concepts. To answer such analytical questions, scientific knowledge has to be applied.
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CSIR UGC NET / JRF June 2019 Exam Pattern
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Joint CSIR-UGC NET will be a single paper with multiple choice questions. Candidate will appear in any one subject. It is a 3 hours duration exam of 200 marks.
Subjects |
- Chemical sciences
- Earth, Atmospheric, Ocean and Planetary Sciences
- Life sciences
- Mathematical Sciences
- Physical sciences
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Marks |
200 |
Duration of exam |
3 hours |
Mode of exam |
Pen and paper based |
Languages in which question paper will be available |
Hindi, English |
Question type |
MCQs |
Morning session timings |
9 am to 12 noon |
Afternoon session timings |
from 2 pm to 5 pm |
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How to Apply about CSIR UGC NET / JRF June 2019 Examination Online Form
1. The Candidates can Apply through Online mode. |
2. Click Apply Online Link is given on Our Website in Important link Section. |
3. Candidates are required to Register before Applying for the Post and Already
Register Candidate Not needs to register Again. |
4.After Successful Registration system will Generate a Login ID and Password on your Screen. |
5. Login with the ID and Password then Start Filling Your Application form and Read all the instruction before Applying for the Post. |
6. Upload the Scanned Copy of Documents in Prescribed Size and format. |
7. Take Printout of your Application form for future Reference. |
8. Online Application can be Submitted on or Before 22nd March 2019. |
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Important Links to Apply for CSIR UGC NET / JRF June 2019 Examination Online Form
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